Question

One of Saturn's moon is named as Mimas. The orbital distance of Mimas is $1.87\times {10}^{8}m$ from Saturn. The mean orbital period of Mimas is approximately 23 hours. Calculate the speed of Mimas with which it revolves around Saturn. Assume the path of the moon to be perfectly circular.

• A. $21,274m/s$
• B. $7,091m/s$
• C. $28,366m/s$
• D. $14,183m/s$

Answer 1

The correct option is D $14,183m/s$

For a uniform circular motion of radius $R$ and time period $T$, speed is given by:
$v=\frac{2\pi R}{T}$

Or,
$v=\frac{2\times 3.14\times 1.87\times {10}^{8}m}{23\times 3600s}$

Or,
$v=14183m/s$

Hence the speed is 14183 m/s