Question

One of the acute angles of a right triangle is ${40}^{\circ }$. Find the other acute angle.

Answer 1

Since, in right angled triangle, an angle must be ${90}^{\circ }$.

It is given that, one of the acute angles of a right triangle is ${40}^{\circ }$.

Let the other angle be $x$.

$\Rightarrow {40}^{\circ }+{90}^{\circ }+x={180}^{\circ }$ [Since, sum of the angles of a triangle is ${180}^{\circ }$.]

$\Rightarrow {130}^{\circ }+x={180}^{\circ }$

$\Rightarrow x={180}^{\circ }-{130}^{\circ }$

$\Rightarrow x={50}^{\circ }$

Thus, the other acute angle is ${50}^{\circ }$