Question

One of the angle of a triangle is ${60}^o$. The smallest angle of the other two angles is half of the greater angle. Find the angles.

Answer 1

Given an angle of a triangle is ${60}^0$ and the smaller of the remaining two is half of the greater angle.

Say, the smaller angle is $x$. Then the greater angle of the two is $2x$.

Now, the sum of angle of a triangle is ${180}^0$.

$\therefore$ $60+x+2x=180$

$3x=120$

$x=40$

$\therefore$ Angles are ${60}^0,x,2x={60}^0,{40}^0,{80}^0$.