Question

One of the angles of a triangle is 110° and the other two angles are equal. What is the measure of each of these equal angles?

Answer 1

Given:
∠A = 110^o and ​∠B = ∠C
Now, the sum of the measures of all the angles of a traingle is 180^o .
∠A + ∠B + ∠C = 180^o
⇒ 110^o + ​∠B + ∠B = 180^o
​ ⇒ 110^o + 2​∠B = 180^o
​ ⇒ 2​∠B = 180^o $-$ 110^o
⇒ 2∠B = 70^o
⇒ ∠B = 70^o / 2
⇒ ∠B = 35^o

∴ ​∠C = 35^o
The measures of the three angles:
∠A = 110^o, ∠B = 35^o, ​∠C = 35^o