Question

One of the angles of a triangle is ${130}^{\circ }$, and the other two angles are equal. What is the measure of each of these equal angles?

Answer 1

Given one of the angles of a triangle is ${130}^{\circ }$
Also given that remaining two angles are equal
So let the second and third angle be x
We know that sum of all the angles of a triangle ${180}^{\circ }$
${130}^{\circ }+x+x={180}^{\circ }$
${130}^{\circ }+2x={180}^{\circ }$
$2x={180}^{\circ }-{130}^{\circ }$
$2x={50}^{\circ }$
$x=50/2$
$x={25}^{\circ }$
Therefore the two other angles are ${25}^{\circ }$ each