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Byju's Answer
Standard VII
Mathematics
Angle Sum Property
One of the an...
Question
One of the angles of a triangle is
40
o
. The difference of other two angles is
20
o
. Find the angles.
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Solution
Let the angles be
∠
A
,
∠
B
,
∠
C
One of the angle be,
∠
A
=
40
∘
Difference between other two is
20
∘
⇒
∠
B
−
∠
C
=
20
∘
−
(
i
)
∴
∠
A
+
∠
B
+
∠
C
=
180
∘
(Sum of all angles of a
△
=
180
∘
)
⇒
40
∘
+
∠
B
+
∠
C
=
180
∘
⇒
∠
B
+
∠
C
=
140
∘
−
(
i
i
)
Solving
(
i
)
and
(
i
i
)
2
∠
B
=
160
∘
⇒
∠
B
=
80
∘
,
∠
C
=
60
∘
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