Question

One of the angles of a triangle is ${65}^o$. Find the remaining two angles, if their difference is ${25}^o$.

• A. ${70}^o,{45}^o$
• B. ${55}^o,{40}^o$
• C. ${50}^o,{85}^o$
• D. ${75}^o,{40}^o$

Answer 1

The correct option is A ${70}^o,{45}^o$

Let one angle be $\angle x$
$\therefore$ other angle is $\angle x+{25}^o$
Now,
We know, by angle sum property, the sum of all angles of a triangles is ${180}^0$.
$⟹x+x+{25}^o+{65}^o={180}^o$
$⟹2x={180}^o-{90}^o$
$⟹x={45}^o$
Thus, the angles are ${45}^o$ and ${70}^o$