Question

One of the angles of a triangle measures 108 degrees and the other two angles are equal. Find the measure of each of the equal angles.
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Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{ABC}\mathrm{be}\mathrm{the}∆. \\ \mathrm{Now},\angle \mathrm{A}=108° \\ \mathrm{Let}\angle \mathrm{B}=\angle \mathrm{C}=\mathrm{x} \\ \mathrm{Now},\mathrm{by}\mathrm{angle}\mathrm{sum}\mathrm{property}: \\ \angle \mathrm{A}+\angle \mathrm{B}+\angle \mathrm{C}=180° \\ \Rightarrow 108+\mathrm{x}+\mathrm{x}=180° \\ \Rightarrow 2\mathrm{x}=72 \\ \Rightarrow \mathrm{x}=36 \\ \mathrm{So},\angle \mathrm{B}=\angle \mathrm{C}=36° \end{gathered}$$