One of the diameter of the circle circumscribing the rectangle ABCD is 4y = x + 7. If A and B are the points (-3, 4) and (5, 4) respectively, then the area of the rectangle is (in square units)
32
AB = 8, M = (1, 4)
Let centre of circle is O(h, k)
∵AB is parallel to X axis
⇒ MN is parallel to Y axis
⇒h=1
Now 4y = x + 7 is a diameter
4k = h + 7
4k = 1 + 7
k = 2
⇒O(1,2)
⇒OM=2
⇒ MN=4
Area =8×4=32