One of the equal angles of an isosceles triangle is 50- Find the third angle of this triangle-

Let the third angle be x^∘. x+50^∘+50^∘=180^∘ ⇒ x^∘+100^∘=180^∘ ⇒ x^∘=180^∘ 100^∘=80^∘ Thus, ∠ x=80^∘ ...

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Byju's Answer

Standard VI

Mathematics

Construction of Triangles When Two Angles and Included Side Are Given

One of the eq...

Question

One of the equal angles of an isosceles triangle is $50^{\circ}$ . Find the third angle of this triangle.

60^{\circ}

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80^{\circ}

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40^{\circ}

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50^{\circ}

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Solution

The correct option is B $80^{\circ}$
Let the third angle be $x^{\circ}$ .

$x + 50^{\circ} + 50^{\circ} = 180^{\circ}$

$\Rightarrow x^{\circ} + 100^{\circ} = 180^{\circ}$

$\Rightarrow x^{\circ} = 180^{\circ} - 100^{\circ} = 80^{\circ}$

Thus, $∠ x = 80^{\circ}$

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Each of the two equal angles of an isosceles triangle is four times the third angle. Find the angles of the triangle.

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One of the equal angles of an isosceles triangle is 50∘. Find the third angle of this triangle.

The correct option is B 80∘Let the third angle be x∘. x+50∘+50∘=180∘ ⇒x∘+100∘=180∘ ⇒x∘=180∘−100∘=80∘ Thus, ∠x=80∘

One of the equal angles of an isosceles triangle is $50^{\circ}$ . Find the third angle of this triangle.

The correct option is B $80^{\circ}$
Let the third angle be $x^{\circ}$ .

$x + 50^{\circ} + 50^{\circ} = 180^{\circ}$

$\Rightarrow x^{\circ} + 100^{\circ} = 180^{\circ}$

$\Rightarrow x^{\circ} = 180^{\circ} - 100^{\circ} = 80^{\circ}$

Thus, $∠ x = 80^{\circ}$