One of the exterior angles of a triangle is $125^{o}$ and the interior opposite angles are in the ratio $2 : 3$ . Find the angles of the triangle.

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Solution

$125^{\circ} = ∠ A + ∠ B$
$125 = 2 X + 3 X$
$125 = 5 X$
$X = 25^{\circ}, 2 X = 50, 3 X = 75$
third angle $= 180 - 125 = 55^{\circ}$

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One of the exterior angles of a triangle is 125o and the interior opposite angles are in the ratio 2:3. Find the angles of the triangle.

125∘=∠A+∠B125=2X+3X125=5XX=25∘,2X=50,3X=75third angle =180−125=55∘

One of the exterior angles of a triangle is $125^{o}$ and the interior opposite angles are in the ratio $2 : 3$ . Find the angles of the triangle.

$125^{\circ} = ∠ A + ∠ B$
$125 = 2 X + 3 X$
$125 = 5 X$
$X = 25^{\circ}, 2 X = 50, 3 X = 75$
third angle $= 180 - 125 = 55^{\circ}$