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Question

One of the exterior angles of a triangle is 80°, and the interior opposite angles are equal to each other. What is the measure of each of these two angles?

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Solution

Let us assume that A and B are the two interior opposite angles. We know that A is equal to B.We also know that the sum of interior opposite angles is equal to the exterior angle.Hence, we can say that:A+B=80° Or,A+A=80° (A=B)2A=80°A=80°2=40°A=B=40°Thus, each of the required angles is of 40°.

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