One of the exterior angles of a triangle is 80°, and the interior opposite angles are equal to each other. What is the measure of each of these two angles?
(2 marks)

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Solution

Let us assume that A and B are the two interior opposite angles.

We know that ∠A is equal to ∠B.

We also know that the sum of interior opposite angles is equal to the exterior angle.

Therefore, we have,

∠A + ∠B = 80°
(0.5 marks)

∠A +∠A = 80° (because ∠A = ∠B)
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2∠A = 80°

∠A = 80/2 = 40°
(0.5 marks)

∠A= ∠B = 40°

Thus, each of the required angles is of 40°.
(0.5 mark)

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One of the exterior angles of a triangle is 80°, and the interior opposite angles are equal to each other. What is the measure of each of these two angles? (2 marks)

One of the exterior angles of a triangle is 80°, and the interior opposite angles are equal to each other. What is the measure of each of these two angles?
(2 marks)