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Question

One of the factors of 4x2−36 is:


A

x+3

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B

x-3

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C

x+5

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D

x - 15

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Solution

The correct options are
A

x+3


B

x-3


The expression 4x236 can be written as

(2x)2(6)2.....(i)

Comparing (i) with the identity a2b2=(a+b)(ab), we get

a2=(2x)2a=2x

b2=62b=6

4x236

=(2x)2(6)2

=(2x+6)(2x6)

=2(x+3)2(x3)

=4(x+3)(x3).

Therefore, the factors of (2x)2(6)2 are (2x+6) and (2x-6) or 4, (x + 3) and (x - 3).


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(x + a)(x +b)= x^2 + x(a+ b) + ab
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