One of the factors of 4x2−36 is:
x+3
x-3
The expression 4x2−36 can be written as
(2x)2−(6)2.....(i)
Comparing (i) with the identity a2−b2=(a+b)(a−b), we get
a2=(2x)2⇒a=2x
b2=62⇒b=6
4x2−36
=(2x)2−(6)2
=(2x+6)(2x−6)
=2(x+3)2(x−3)
=4(x+3)(x−3).
Therefore, the factors of (2x)2−(6)2 are (2x+6) and (2x-6) or 4, (x + 3) and (x - 3).