One of the factors of $x^{3} - 2 x^{2} + 2 x - 1$ is

x - 1

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x + 1

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x - 2

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x + 2

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Solution

The correct option is A
x - 1

$x^{3} - 2 x^{2} + 2 x - 1 = x^{3} - x^{2} - x^{2} + x + x - 1$

= $x^{2} (x - 1) - x (x - 1) + 1 (x - 1)$

= $(x - 1) (x^{2} - x + 1)$

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Similar questions

x^{3} - 2 x^{2} + 2 x - 1

x^{3} + 2 x^{2} + 2 x + 1

Question :

One of the factors of x⁵+x+1 is

(1) 2x² - x - 1

(2) x³ - x²+ 1

(3) x² - 2x² + 1

(4) x³ + x² + 1

\frac{2 x^{2} + 2 x + 1}{x^{3} + x^{2}} =

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