One of the hazards of the nuclear explosion is the generation of $^{90} S r$ and its subsequent incorporation in bones. This nuclide has a half-life of $28.1$ years. Suppose one microgram was absorbed by a new-born child, how much $^{90} S r$ will remain in his bones after $20$ years?

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Solution

$t = \frac{2.303}{λ} log \frac{i n i t i a l}{r e m a i n i n g}$
$λ = \frac{0.693}{28.1}, t = 20 y$ , initial $= 1 μ g$ , remaining $= x μ g$
$20 = \frac{2.303}{0.693} \times 28.1 log (\frac{1}{x})$
$x = 0.61 μ g$

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Q. One of the hazards of nuclear explosion is the generation of

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One of the hazards of the nuclear explosion is the generation of 90Sr and its subsequent incorporation in bones. This nuclide has a half-life of 28.1 years. Suppose one microgram was absorbed by a new-born child, how much 90Sr will remain in his bones after 20 years?

t=2.303λloginitialremainingλ=0.69328.1,t=20y, initial=1μg, remaining =xμg20=2.3030.693×28.1log(1x)x=0.61μg

One of the hazards of the nuclear explosion is the generation of $^{90} S r$ and its subsequent incorporation in bones. This nuclide has a half-life of $28.1$ years. Suppose one microgram was absorbed by a new-born child, how much $^{90} S r$ will remain in his bones after $20$ years?

$t = \frac{2.303}{λ} log \frac{i n i t i a l}{r e m a i n i n g}$
$λ = \frac{0.693}{28.1}, t = 20 y$ , initial $= 1 μ g$ , remaining $= x μ g$
$20 = \frac{2.303}{0.693} \times 28.1 log (\frac{1}{x})$
$x = 0.61 μ g$