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Standard XII

Mathematics

Perpendicular Distance of a Point from a Line

One of the li...

Question

One of the lines of $- 3 x^{2} + 2 x y + y^{2} = 0$ is parallel to $l x + y + 1 = 0$ then $l =$

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Solution

The correct option is C $- 1$
$y^{2} + 3 x - x y - 3 x^{2} = 0 y (y + 3 x) - x (y + 3 x) = 0 (y + 3 x) (y - x) = 0$
lines are $x = y$ and $- 3 x$
On comparing , we get
$l = 3$ or $l = - 1$

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One of the lines of −3x2+2xy+y2=0 is parallel to lx+y+1=0 then l=

The correct option is C −1y2+3x−xy−3x2=0y(y+3x)−x(y+3x)=0(y+3x)(y−x)=0lines are x=y and −3xOn comparing , we get l=3 or l=−1

One of the lines of $- 3 x^{2} + 2 x y + y^{2} = 0$ is parallel to $l x + y + 1 = 0$ then $l =$

The correct option is C $- 1$
$y^{2} + 3 x - x y - 3 x^{2} = 0 y (y + 3 x) - x (y + 3 x) = 0 (y + 3 x) (y - x) = 0$
lines are $x = y$ and $- 3 x$
On comparing , we get
$l = 3$ or $l = - 1$