Question

One of the methods of producing $He$ is to bombard $Li$ with the following projectile

• A. $\alpha$ -particles
• B. electrons
• C. protons
• D. neutrons

Answer 1

The correct option is C protons

The reaction : ${}_3^{7}Li{+}_Z^{A}X\to 2$ ${}_2^{4}He$

Conservation of mass number : $7+A=8$ $⟹A=1$

Conservation of atomic number : $3+Z=4$ $⟹Z=1$

Thus the projectile $X$ will be a proton i.e. ${}_1^{1}H$