One of the number of pythagorean triplet is 6, what can be the other two numbers?
Given number of the triplet is 6
We know that m2−1, 2m, m2+1 is a pythagorean triplet
Let, 2m = 6
m = 3
m2−1 = 32−1 = 9 - 1 = 8
m2+1 = 32+1 = 9 + 1 = 10
So the other two numbers can be 8, 10.