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Standard XII

Chemistry

Characteristics of Equilibrium Constant

One of the re...

Question

One of the reaction that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and $C O_{2}$ .
$F e O (s) + C O (g) ⇌ F e (s) + C O_{2} (g)$
$; K_{p} = 0.265$ atm at 1050 K.
What are the equilibrium partial pressures of $C O$ and $C O_{2}$ respectively at 1050 K if the initial partial pressures are: $P_{C O} = 1.4$ atm and $P_{C O_{2}} = 0.80$ atm?

P_{C O} = 1.739 atm and P_{C O_{2}} = 0.461 a t m

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P_{C O} = 17.39 atm and P_{C O_{2}} = 0.461 a t m

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P_{C O} = 1.79 atm and P_{C O_{2}} = 0.46 a t m

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P_{C O} = 2.739 atm and P_{C O_{2}} = 1.461 a t m

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Solution

The correct option is A $P_{C O} = 1.739 atm and P_{C O_{2}} = 0.461 a t m$

$F e O (s) + C O (g) ⇌ F e (s) + C O_{2} (g) t = 0 1.4 a t m 0.8 a t m at equil (1.4 + x) 0.8 - x Q = \frac{0.8}{1.4} = \frac{4}{7} = 0.55$
$∵ Q > K$ , system is not at equilibrium and to attain equilibrium it will shift in backward direction
$K_{p} = 0.265 = \frac{0.8 - x}{1.4 + x}$
On solving, x = 0.339
$∴ P_{C O} = 1.4 + x = 1.4 + 0.339 = 1.739$
$and P_{C O_{2}} = 0.8 - x = 0.8 - 0.339 = 0.461 a t m$

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Similar questions

One of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and CO₂.

FeO (s) + CO (g) Fe (s) + CO₂ (g); K_p= 0.265 at 1050 K.

What are the equilibrium partial pressures of CO and CO₂ at 1050 K if the initial partial pressures are: p_CO = 1.4 atm and = 0.80 atm?

Q. One of the reaction that takes place to producing steel from iron ore is the reduction of iron(III) oxide by carbon monoxde to give iron metal and

{C O}_{2}

F e O (s) + C O (g) ⇌ F e (s) + {C O}_{2} (g); K_{p} = 0.265

What are the equilibrium partial pressures of

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{C O}_{2}

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if the initial partial pressures are:

p_{C O} = 1.4 a t m

and

p_{{C O}_{2}} = 0.80 a t m

Q. One of the reaction that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and

C O_{2}

F e O (s) + C O (g) ⇌ F e (s) + C O_{2} (g)

; K_{p} = 0.265

atm at 1050 K.
What are the equilibrium partial pressures of

C O

and

C O_{2}

respectively at 1050 K if the initial partial pressures are:

P_{C O} = 1.4

atm and

P_{C O_{2}} = 0.80

atm?

One of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and CO₂. FeO (s) + CO (g) Fe (s) + CO₂ (g); K_p= 0.265 at 1050 K. What are the equilibrium partial pressures of CO and CO₂ at 1050 K if the initial partial pressures are: p_CO = 1.4 atm and CO₂ = 0.80 atm?