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Concentration Terms

One of the re...

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One of the reaction that takes place in producing steel from iron ore is the reduction of iron(II) oxide by carbon monoxide to give iron metal and $C O_{2} . F e O (s) + C O (g) ⇌ F e (s) + C O_{2} (g); K_{P} = 0.265$ atm at 1050K. What are the equilibrium partial pressures of CO and $C O_{2}$ respectively at 1050 K if the initial partial pressures are: $P_{C O} = 1.4$ atm and $p_{C O_{2}} = 0.80 a t m ?$

A

P_{C O} = 1.739 a t m a n d P_{C O_{2}} = 0.461 a t m

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B

P_{C O} = 17.39 a t m a n d P_{C O_{2}} = 0.461 a t m

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C

P_{C O} = 1.79 a t m a n d P_{C O_{2}} = 0.46 a t m

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D

P_{C O} = 2.739 a t m a n d P_{C O_{2}} = 1.461 a t m

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Solution

The correct option is A $P_{C O} = 1.739 a t m a n d P_{C O_{2}} = 0.461 a t m$
$\begin{matrix} F e O (s) & + & C O (g) & ⇌ & F e (s) & + & C O_{2} (g) t = 0 & 1.4 a t m & 0.8 a t m \end{matrix}$
_________________________________________________
$\begin{matrix} A t e q u i l & (1.4 + x) & 0.8 - x \end{matrix}$

$Q = \frac{0.8}{1.4} = \frac{4}{7} = 0.57$
$∵ Q > K,$ system is not at equilibrium and to attain equilibrium it will shift in backward direction
$K_{P} = 0.265 = \frac{0.8 - x}{1.4 + x}$
On solving, x = 0.339
$∴ [P_{C O}] = 1.739$ atm and $P_{C O_{2}} = 0.461$ atm

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Similar questions

Q. One of the reaction that takes place in producing steel from iron ore is the reduction of iron(II) oxide by carbon monoxide to give iron metal and

C O_{2}

F e O (s) + C O (g) ⇌ F e (s) + C O_{2} (g)

K_{P} = 0.265 a t m

1050 K

. What are the equilibrium partial pressures of CO and

C O_{2}

respectively at 1050K if the initial partial pressures are:

p_{c o} = 1.4 a t m

p_{c o_{2}} = 0.80 a t m

?

Q. One of the reaction that takes place to producing steel from iron ore is the reduction of iron(III) oxide by carbon monoxde to give iron metal and

{C O}_{2}

F e O (s) + C O (g) ⇌ F e (s) + {C O}_{2} (g); K_{p} = 0.265

What are the equilibrium partial pressures of

C O

{C O}_{2}

1050 K

if the initial partial pressures are:

p_{C O} = 1.4 a t m

p_{{C O}_{2}} = 0.80 a t m

Q. One of the reaction that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and

C O_{2}

F e O (s) + C O (g) ⇌ F e (s) + C O_{2} (g)

; K_{p} = 0.265

atm at 1050 K.
What are the equilibrium partial pressures of

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C O_{2}

respectively at 1050 K if the initial partial pressures are:

P_{C O} = 1.4

P_{C O_{2}} = 0.80

One of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and CO₂. FeO (s) + CO (g) Fe (s) + CO₂ (g); K_p= 0.265 at 1050 K. What are the equilibrium partial pressures of CO and CO₂ at 1050 K if the initial partial pressures are: p_CO = 1.4 atm and CO₂ = 0.80 atm?

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3.0

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