Question

One of the rectangular components of a force of $40N$ is $20N$. Find the angle it makes with this component and magnitude of other component.

Answer 1

Let the angle made by the force with the $20N$ component be $\Theta$.

Then , $40cos\Theta$ = $20$

cos$\Theta$ = $\frac{1}{2}$

$\Theta$ = ${60}^{\circ }$

Magnitude of the other component = $\left|40sin\right(\Theta \left)\right|$

= $\left|40sin\right({60}^{\circ }\left)\right|$

= $20\sqrt{3}N$