One of the roots of the equation (x+1a)2−b2=0 is .
Root of the equation (x+1a)2−b2=0 is
If a and b are the roots of the equation, x2 – 6x + 1 = 0, then the value of a2 + b2 is __
If a, b are the roots of the equation x2+x+1=0, then a2+b2=
x2+a2x+b=0 and x2+x+1=0 have a common roots which of the following is true.