One of the roots of the given equation ∣∣
∣∣x+abcbx+cacax+b∣∣
∣∣=0 is
A
-(a+b)
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B
-(b+c)
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C
-a
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D
-(a+b+c)
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Solution
The correct option is D -(a+b+c) ∣∣
∣∣x+abcbx+cacax+b∣∣
∣∣=0⇒(x+a+b+c)∣∣
∣∣1bc1x+ca1ax+b∣∣
∣∣=0,(C1→C1+C2+C3)⇒x=−(a+b+c)is one of the root of the equation.