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Question

One of the roots of the given equation ∣ ∣x+abcbx+cacax+b∣ ∣=0 is

A
-(a+b)
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B
-(b+c)
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C
-a
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D
-(a+b+c)
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Solution

The correct option is D -(a+b+c)
∣ ∣x+abcbx+cacax+b∣ ∣=0(x+a+b+c)∣ ∣1bc1x+ca1ax+b∣ ∣=0,(C1C1+C2+C3)x=(a+b+c) is one of the root of the equation.

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