Question

One of the straight line in the figure depicts the dependence of work done |W| on the temperature variations T for an isobaric process. The two of following are the adiabatic curves for argon and nitrogen. The isobaric process which depicts both the gases is

Answer 1

for argon $f=3$ for nitrogen $f=5$

for isobaric process $\left|\Delta w\right|=nRT$

for adiaboric process $\left|\Delta w\right|=\frac{nR\Delta T}{1-\gamma }$

$\therefore$ for argon:$\left|w\right|$ for adiabatic

$\left|w\right|=\frac{3nR\Delta T}{2}$

for nitrogen $\left|w\right|$ for ad basic.

$\left|w\right|=\frac{5nR\Delta T}{2}$

$\therefore$ graph $\left(2\right)$ has greaters slope so it is for nitrogen aliabasic. graph $\left(3\right)$ is for argon adiabatic & graph (4) is for isobaric.