One of the two digit of a two digit number is 3 times the other digit if you interchange the digit of these two digit number and and the resulting number to the original number you get 88 what is the original number

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Solution

Let the digit in units place = x
The digit in tens place = 3x
The number is 10(3x) + x = 31x

Digits are interchanged
Digit in units place = 3x
Digit in tens place = x

The new number= 10(x) + 3x = 13x

Sum of these two numbers = 88

31x + 13x = 88

44x = 88

x = 2

3x = 6

The original number is 62

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One of the two digits of a two digit number is three times the other digit . If you interchange the digits of this two digit number and add the resulting number to the original number you get $88$ .What is the original number ?

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One of the two digit of a two digit number is 3 times the other digit if you interchange the digit of these two digit number and and the resulting number to the original number you get 88 what is the original number

Let the digit in units place = x The digit in tens place = 3x The number is 10(3x) + x = 31x Digits are interchanged Digit in units place = 3x Digit in tens place = x The new number= 10(x) + 3x = 13x Sum of these two numbers = 88 31x + 13x = 88 44x = 88 x = 2 3x = 6 The original number is 62