One of the two digits of a two-digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88 .What is the original number?
A
62
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B
61
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C
66
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D
64
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Solution
The correct option is A62 Let one's digit be x. Then, ten's digit =3x. ∴ Number = 10×3x+x=30x+x=31x .........(1) Number obtained by reversing the digits =10x+3x=13x It is given that the sum of the original number and reversed number is 88. ∴31x+13x=88 ⇒44x=88⇒x=884=2 Putting the value of x in (1) , we get number =31×2=62