Question

One of the two digits of a two-digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get $88$ .What is the original number?

• A. $62$
• B. $61$
• C. $66$
• D. $64$

Answer 1

The correct option is A $62$

Let one's digit be $x$. Then, ten's digit $=3x$.
$\therefore$ Number = 10$\times 3x+x=30x+x=31x$ .........(1)
Number obtained by reversing the digits $=10x+3x=13x$
It is given that the sum of the original number and reversed number is $88$.
$\therefore 31x+13x=88$
$\Rightarrow 44x=88\Rightarrow x=\frac{88}{4}=2$
Putting the value of $x$ in (1) , we get number $=31\times 2=62$