Question

One of the two events must occur. If the chance of one is $\frac{2}{3}$ of the other, then odds in favour of the other are

• A.
• B.
• C.
• D.

Answer 1

The correct option is D

Let p be the probability of the other event, then the probability of the first event is $\frac{2}{3}$ p. Since two events are totally exclusive, we have $p+\left(\frac{2}{3}\right)p=1\Rightarrow p=\frac{3}{5}$
Hence odds in favour of the other are 3 : 5 – 3, i.e, 3 : 2.