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Question

One of the two identical conducting wires of length L is bent in the form of a circular loop and the other one into a circular coil of N identical turns. If the same current is passed in both, the ratio of the magnetic field at the central of the loop (BL) to that at the centre of the coil (BC), i.e. R BLBC will be

A
1N
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B
N2
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C
1N2
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D
N
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Solution

The correct option is C 1N2

L=2πR L=N×2πr
R=Nr
BL=μ0i2R ............(1)

BC=μ0Ni2r

BC=μ0N2i2R........(2)

eqn. 1 divided by 2.

BLBC=1N2

1142472_1330023_ans_7fa3ee3d3773441397b14512add707b9.png

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