Question

One of the values given in brackets next to each equation satisfies the equation . Find that value .

$5a+3=43$ $\left(5,8,10,12\right)$

Answer 1

Given , the linear equation is $5a+3=43---------\left(1\right)$

Putting $a=5$ in equation $\left(1\right)$ we get ,

LHS$=5\times 5+3$

$=25+3$

$=28$

Since, LHS $\ne$RHS $\ne$$43$

So, $a=5$ is not solution of the given equation .

Putting $a=8$ in equation $\left(1\right)$ we get ,

LHS$=5\times 8+3$

$=40+3$

$=43$

Since, LHS $=$RHS $=$$43$

Hence , $a=8$ is satisfies the given equation .