One of the zeros of the polynomial $2 x^{2} + 7 x - 4$ is:

2

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\frac{1}{2}

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- \frac{1}{2}

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- 2

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Solution

The correct option is B $\frac{1}{2}$
To find the zero of $2 x^{2} + 7 x - 4$ is same as solving the equation $2 x^{2} + 7 x - 4 = 0$
$\Rightarrow 2 x^{2} + 8 x - x - 4 = 0$
$\Rightarrow 2 x (x + 4) - 1 (x + 4) = 0$
$\Rightarrow (2 x - 1) (x + 4) = 0$
$\Rightarrow (2 x - 1) = 0, (x + 4) = 0$
$\Rightarrow x = \frac{1}{2}, - 4$
Therefore, option $B$ is correct.

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Similar questions

Q. Question 10
One of the zeroes of the polynomial is

2 x^{2} + 7 x - 4

A) $2$
B) $\frac{1}{2}$
C) $- \frac{1}{2}$
D) $- 2$

The zeros of the polynomial $p (x) = 2 x^{2} + 7 x - 4$ are
(a) $4, \frac{- 1}{2}$
(b) $4, \frac{1}{2}$
(c) $- 4, \frac{1}{2}$
(d) $- 4, \frac{- 1}{2}$

Q. Question 10
One of the zeroes of the polynomial is

2 x^{2} + 7 x - 4

A) $2$
B) $\frac{1}{2}$
C) $- \frac{1}{2}$
D) $- 2$

Q. On of the zeros of the polynomial f(x) = 2x² + 7x – 4 is
(a) 2
(b)

\frac{1}{2}

(c)

- \frac{1}{2}

(d) –2

Q. If 2 and

\frac{- 1}{3}

are the zeros of the polynomial 3x³ − 2x² − 7x − 2, find the third zero of the polynomial.

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One of the zeros of the polynomial 2x2+7x−4 is:

The correct option is B 12To find the zero of 2x2+7x−4 is same as solving the equation 2x2+7x−4=0⇒2x2+8x−x−4=0⇒2x(x+4)−1(x+4)=0⇒(2x−1)(x+4)=0⇒(2x−1)=0,(x+4)=0⇒x=12,−4Therefore, option B is correct.

One of the zeros of the polynomial $2 x^{2} + 7 x - 4$ is: