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Standard XII

Chemistry

Reaction Quotient

One reaction ...

Question

One reaction that occurs in producing steel from iron ore is the reduction of iron ore(II) by carbon monoxide to give iron metal and carbon dioxide. The equilibrium constant $K_{p}$ for the reaction at 1000K is 0.259. $F e O + C O ⇋ F e + C O_{2}$ . If the initial partial pressure of CO and $C O_{2}$ are 1 atm and 0.5 atm respectively, the equilibrium partial pressures of CO and $C O_{2}$ at 1000K are :

1.191 atm, 0.309 atm

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0.309 atm, 1.191 atm

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1.191 atm for both

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0.309 atm for both

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Solution

The correct option is A 1.191 atm, 0.309 atm
$C O$ $C O_{2}$
Initial partial pressure 1 0.5
Equilibrium partial pressure 1-x 0.5+x
The equilibrium constant is $K_{p} = \frac{P_{C O_{2}}}{P_{C O}}$ .
Substitute values: $0.259 = \frac{0.5 + x}{1 - x}$ .
Hence, $x = - 0.191$ .
Hence, the equilibrium partial pressures of $C O$ and $C O_{2}$ are 1.191 atm, 0.309 atm respectively.

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Similar questions

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; K_{p} = 0.265

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