You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Reaction Quotient

One reaction ...

Question

One reaction that occurs in producing steel from iron ore is the reduction of iron ore(II) by carbon monoxide to give iron metal and carbon dioxide. The equilibrium constant $K_{p}$ for the reaction at 1000K is 0.259. $F e O + C O ⇋ F e + C O_{2}$ . If the initial partial pressure of CO and $C O_{2}$ are 1 atm and 0.5 atm respectively, the equilibrium partial pressures of CO and $C O_{2}$ at 1000K are :

1.191 atm, 0.309 atm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.309 atm, 1.191 atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.191 atm for both

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.309 atm for both

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 1.191 atm, 0.309 atm
$C O$ $C O_{2}$
Initial partial pressure 1 0.5
Equilibrium partial pressure 1-x 0.5+x
The equilibrium constant is $K_{p} = \frac{P_{C O_{2}}}{P_{C O}}$ .
Substitute values: $0.259 = \frac{0.5 + x}{1 - x}$ .
Hence, $x = - 0.191$ .
Hence, the equilibrium partial pressures of $C O$ and $C O_{2}$ are 1.191 atm, 0.309 atm respectively.

Suggest Corrections

Similar questions

Q. One of the reaction that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and

C O_{2}

F e O (s) + C O (g) ⇌ F e (s) + C O_{2} (g)

; K_{p} = 0.265

atm at 1050 K.
What are the equilibrium partial pressures of

C O

and

C O_{2}

respectively at 1050 K if the initial partial pressures are:

P_{C O} = 1.4

atm and

P_{C O_{2}} = 0.80

atm?

Q. One of the reaction that takes place in producing steel from iron ore is the reduction of iron(II) oxide by carbon monoxide to give iron metal and

C O_{2}

F e O (s) + C O (g) ⇌ F e (s) + C O_{2} (g)

;

K_{P} = 0.265 a t m

1050 K

. What are the equilibrium partial pressures of CO and

C O_{2}

respectively at 1050K if the initial partial pressures are:

p_{c o} = 1.4 a t m

and

p_{c o_{2}} = 0.80 a t m

Q. One of the reaction that takes place in producing steel from iron ore is the reduction of iron(II) oxide by carbon monoxide to give iron metal and

C O_{2} . F e O (s) + C O (g) ⇌ F e (s) + C O_{2} (g); K_{P} = 0.265

atm at 1050K. What are the equilibrium partial pressures of CO and

C O_{2}

respectively at 1050 K if the initial partial pressures are:

P_{C O} = 1.4

atm and

p_{C O_{2}} = 0.80 a t m ?

One of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and CO₂. FeO (s) + CO (g) Fe (s) + CO₂ (g); K_p= 0.265 at 1050 K. What are the equilibrium partial pressures of CO and CO₂ at 1050 K if the initial partial pressures are: p_CO = 1.4 atm and CO₂ = 0.80 atm?

Q. One of the reaction that takes place to producing steel from iron ore is the reduction of iron(III) oxide by carbon monoxde to give iron metal and

{C O}_{2}

F e O (s) + C O (g) ⇌ F e (s) + {C O}_{2} (g); K_{p} = 0.265

What are the equilibrium partial pressures of

C O

and

{C O}_{2}

1050 K

if the initial partial pressures are:

p_{C O} = 1.4 a t m

and

p_{{C O}_{2}} = 0.80 a t m

Join BYJU'S Learning Program