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Question

One root of the following given equation 2x5−14x4+31x3−64x2+19x+130=0 is


A

1

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B

3

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C

5

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D

7

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Solution

The correct option is C

5


We can solve this problem using options given -
On putting x = 5, we get

2(5)514(5)4+31(5)364(5)2+19(5)+130=0

Hence x = 5 satisfies the given equation.

Thus 5 is a root of the equation.
Other options will not satisfy the given equation so the answer is x = 5.


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