Question

One root of the quadratic equation $x^2+px+3=0$ is $1$. Its other root is

• A. $-3$
• B. $0$
• C. $3$
• D. $4$

Answer 1

The correct option is C $3$

$1$ is the root of the given quadratic equation. Thus,

$(1{)}^2+p(1)+3=0$

$p+4=0$

$p=-4$

Thus, the equation becomes $x^2-4x+3=0$

$x^2-x-3x+3=0$

$x(x-1)-3(x-1)=0$

$(x-1)(x-3)=0$

$x=1,3$

Hence, the other root of the equation is 3.