One sees the top of a tree on a bank of a river at an elevation of 70∘ from the other bank. Stepping 20 m back, he sees the top of the tree at an elevation of 55∘. If height of the person is 1.4 m then the width of river is [tan 70∘=2.75, tan 55∘=1.43]
21.66 m
Let the width of river be AB = X and the person was standing initially at point C and step back 20 m to reach at D. Height CF of person being 1.4 m.
In Right -angled △ ABC
tan 70∘=ABAC=ABx
AB=x.tan 70∘=x×2.75=2.75 x ...(1)
In Right -angled △ABD
tan 55∘=ABAD=AB(x+20)
AB=(x+20). Tan 55∘ = 1.43 (x+20) ...(2)
from 1 and 2 we have
2.75x=1.43 (x+20)2.75x=1.43x+28.61.32x=28.6x=21.66 mHence, the width of the river is 21.66 m