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Question

One sees the top of a tree on a bank of a river at an elevation of 70 from the other bank. Stepping 20 m back, he sees the top of the tree at an elevation of 55. If height of the person is 1.4 m then the width of river is [tan 70=2.75, tan 55=1.43]


A

26.4 m

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B

21.66 m

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C

28.2 m

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D

25.4 m

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Solution

The correct option is B

21.66 m


Let the width of river be AB = X and the person was standing initially at point C and step back 20 m to reach at D. Height CF of person being 1.4 m.

In Right -angled ABC

tan 70=ABAC=ABx

AB=x.tan 70=x×2.75=2.75 x ...(1)

In Right -angled ABD

tan 55=ABAD=AB(x+20)

AB=(x+20). Tan 55 = 1.43 (x+20) ...(2)

from 1 and 2 we have

2.75x=1.43 (x+20)2.75x=1.43x+28.61.32x=28.6x=21.66 mHence, the width of the river is 21.66 m


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