One side of a glass slab is silvered as shown in the figure. A ray of light is incident on the other side at an angle of incident of 45∘. Refractive index of glass is √2. The deflection suffered by the light ray when it comes out of slab will be
On drawing a ray diagram of the given situation based on law of symmetry and laws of reflection and refraction.
We can see that,
∠B=∠A=45∘ [ alternate angle]
Applying Snell's law and law of reflection, ∠C=45∘
So, in △BCD,
∠B+∠C+∠D=180∘
⇒45∘+45∘+δ=180∘
⇒δ=90∘
[anticlockwise]
Why this question? It challenges you to apply the fundamental concept of reflection, refraction and deviation of a light ray. |