Question

One side of a parallelogram is 4.8cm and the other side is $\frac{3}{2}$ times the first side, find the perimeter of the parallelogram.

Answer 1

Let $\square$ABCD be a parallelogram in which AB = 4.8 cm and BC = $\frac{3}{2}$ × AB.
Then, we have:
BC = $\frac{3}{2}$ × 4.8 cm = 7.2 cm

We know that opposite sides of a parallelogram are congruent.
$\Rightarrow$AD = BC = 7.2 cm and CD = AB = 4.8 cm
Now,
Perimeter of parallelogram ABCD = AB + BC + CD + DA
= 4.8 + 7.2 + 4.8 + 7.2
= 24 cm