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Byju's Answer
Standard IX
Mathematics
Properties of Distance
One side of a...
Question
One side of a rectangle lose along the line 4x + 7y + 5 = 0. Two of its opposites vertices are ( -3,1) and (1,1). Find the equations of the lines containing other three sides.
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Similar questions
Q.
One side of a rectangle lies along the line
4
x
+
7
y
+
5
=
0
. Two of its vertices are
(
−
3
,
1
)
and
(
1
,
1
)
. Then find the equations of other sides.
Q.
One side of a rectangle lies along the line 4x + 7y + 5 = 0. Two of its vertices are (-3, 1) and (1, 1). Which of the following is not an equation of the other three straight lines?
Q.
One side of a rectangle lies along the line
4
x
+
7
y
+
5
=
0
and two vertices are
(
−
3
,
1
)
,
(
1
,
1
)
then the remaining vertices are,
Q.
Assertion :One side of a rectangle lies along the line
4
x
+
7
y
+
5
=
0
. Two of its vertices are
(
−
3
,
1
)
and
(
1
,
1
)
. Equation of the side farthest from the origin is
7
x
−
4
y
+
25
=
0
Reason: If
a
and
b
are constants
(
a
,
b
≠
0
)
and
c
is a variable, then from the lines
a
x
+
b
y
+
c
=
0
and
b
x
−
a
y
−
c
=
0
the line farthest from the origin is the one for which
|
c
|
is least.
Q.
Two sides of a parallelogram are along the lines
4
x
+
5
y
=
0
and
7
x
+
2
y
=
0
. If the equation of one of the diagonals of the parallelogram is
11
x
+
7
y
=
9
, then other diagonal passes through the point
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