Question

One side of an equilateral triangle is 8 cm. Its area is

• A. $16\sqrt{3}$ $c{m}^2$
• B. $12\sqrt{3}$ $c{m}^2$
• C. $8\sqrt{3}$ $c{m}^2$
• D. $4\sqrt{3}$ $c{m}^2$

Answer 1

The correct option is A $16\sqrt{3}$ $c{m}^2$

Given, one side of equilateral triangle $=8cm$
Area of an equilateral triangle with length of side $a=\frac{\sqrt{3}}{4}{a}^2$
Hence, area of the given triangle $=\frac{\sqrt{3}}{4}\times 8^2=16\sqrt{3}{cm}^2$