Question

One term in the given number series is wrong. Find out the term.
$196,169,144,121,101$

• A. $101$
• B. $121$
• C. $196$
• D. $169$

Answer 1

The correct option is A $101$

$196,169,144,121,101$

A closer look at the series reveals that each is a perfect square except for $101.$

i.e, $196={14}^2$

$169={13}^2$

$144={12}^2$

$121={11}^2$

$\therefore$ the odd one out in the above square is $101.$

Hence, the answer is $101.$