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Question

One mole of an ideal monoatomic gas is initially at 500 K. If 300 J of heat is added at constant volume, the final temperature of the gas is
(Assume R=8 J/mol K)

A
525 K
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B
550 K
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C
600 K
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D
625 K
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Solution

The correct option is A 525 K
Given, that gas is monoatomic
No. of moles of the gas (n)=1
Heat supplied (Q)=200 J
Initial temperature (Ti)=500 K
For monoatomic gas, CV=3R2

Since volume is constant, work done is zero.
From First law of thermodynamics, we know that
ΔQ=ΔU+W
W=0ΔQ=ΔU
ΔQ=ΔU=nCVΔT
ΔQ=3R2×(TfTi)
300=32×8(Tf500)
Tf=525 K is the final temperature.

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