One mole of an ideal monoatomic gas is taken at a temperature of 300K. If the volume is doubled keeping its pressure constant, change in internal energy is
A
450R
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
600R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
500R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
400R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A450R Given, n=1 f=3[ monoatomic ] T1=300K
As volume is doubled keeping pressure constant, temperature will be doubled. Using Charle's Law, ∴T2=600K ΔT=300K
We know, change in internal energy ΔU=nfRΔT2 =1×3×R×3002=450R
Change in internal energy is 450R when volume is doubled.