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Equipartition Theorem

One mole of a...

Question

One $mole$ of an ideal monoatomic gas is taken at a temperature of $300 K$ . If the volume is doubled keeping its pressure constant, change in internal energy is

450 R

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600 R

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500 R

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400 R

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Solution

The correct option is A $450 R$
Given,
$n = 1$
$f = 3$ $[$ monoatomic $]$
$T_{1} = 300 K$
As volume is doubled keeping pressure constant, temperature will be doubled. Using Charle's Law,
$∴ T_{2} = 600 K$
$Δ T = 300 K$
We know, change in internal energy
$Δ U = \frac{n f R Δ T}{2}$
$= \frac{1 \times 3 \times R \times 300}{2} = 450 R$
Change in internal energy is $450 R$ when volume is doubled.

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Equipartition Theorem

Standard XIII Physics

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One mole of an ideal monoatomic gas is taken at a temperature of 300 K. If the volume is doubled keeping its pressure constant, change in internal energy is

One $mole$ of an ideal monoatomic gas is taken at a temperature of $300 K$ . If the volume is doubled keeping its pressure constant, change in internal energy is