One thousand small water drops of equal size combine to form a big drop. The ratio of the final surface energy to the total initial surface energy is:

10:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1:10

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1000:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1:1000

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 1:10
Small drop radius $= r$
Large drop radius $= R$
Volume equating $\to 1000 r^{3} = R^{3}$
$\Rightarrow 10 r = R$
$\frac{S E_{f}}{S E_{i}} = \frac{4 π R^{2} T}{10004 π r^{2} T}$ $= \frac{(10 r)^{2}}{1000 r^{2}}$ $= \frac{1}{10}$

Suggest Corrections

Similar questions

One thousand small water droplets of equal size combine to form a big drop. The ratio of the final surface energy to the initial surface energy is: (Surface tension of water = 70 dyne/cm)

8000

identical water drops combine together to form a big drop. Then the ratio of the final surface energy to the initial surface energy of all the drops together is:

Q. 8000 identical water drops are combined to form a big drop. then the ratio of final surface energy to the initial surface energy of all drops together

Q. A big water drop is formed by the combination of

^{'} n^{'}

small water drops of equal radii. The ratio of the surface energy of

^{'} n^{'}

drops to the surface energy of big drop is

Q. A big drop is formed by combining

27

small droplets of water. What will be the change in the surface energy?
Then the ratio of the surface energy of big drop to the surface energy of

27

small droplets is p:q. Find p+q

Join BYJU'S Learning Program

One thousand small water drops of equal size combine to form a big drop. The ratio of the final surface energy to the total initial surface energy is:

The correct option is B 1:10Small drop radius =rLarge drop radius =RVolume equating →1000r3=R3⇒10r=RSEfSEi=4πR2T10004πr2T=(10r)21000r2=110

The correct option is B 1:10
Small drop radius $= r$
Large drop radius $= R$
Volume equating $\to 1000 r^{3} = R^{3}$
$\Rightarrow 10 r = R$
$\frac{S E_{f}}{S E_{i}} = \frac{4 π R^{2} T}{10004 π r^{2} T}$ $= \frac{(10 r)^{2}}{1000 r^{2}}$ $= \frac{1}{10}$