One ticket is selected at random from 100 tickets numbered 00,01,02,⋯,98,99. If x1 and x2 denotes the sum and product of the digits on the tickets, then P(x1=9/x2=0) is equal to
A
219
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B
19100
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C
150
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D
None of these
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Solution
The correct option is A219 Let the number selected be xy. Then x+y=9=x1,0≤x,y≤9 and xy=0=x2⇒x=0,y=9 or y=0,x=9 P(x1=9/x2=0)=P(x1=9∩x2=0)P(x2=0)
Now, P(x2=0)=19100 and P(x1=9∩x2=0)=2100 ⇒P(x1=9/x2=0)=2/10019/100=219