Question

One tin holds $12\frac{3}{4}$ litres of oil. How many litres of oil can 26 such tins hold?

Answer 1

Capacity of 1 tin = $12\frac{3}{4}\mathrm{L}=\frac{51}{4}\mathrm{L}$
∴ Capacity of 26 such tins =$\left(26\times \frac{51}{4}\right)\mathrm{L}$
=$\left(\frac{26}{1}\times \frac{51}{4}\right)\mathrm{L}=\left(\frac{26\times 51}{1\times 4}\right)\mathrm{L}=\left(\frac{13\times 51}{1\times 2}\right)\mathrm{L}=\left(\frac{663}{2}\right)\mathrm{L}=331\frac{1}{2}\mathrm{L}$

Hence, 26 such tins can hold $331\frac{1}{2}$ L of oil.