Question

One type of liquid contains 25 % of benzene, the other contains 30% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture.

Answer 1

Let the percentage of benzene = x

$\Rightarrow \frac{30-x}{x-25}=\frac{6}{4}=\frac{3}{2}$

$\Rightarrow 60-2x=3x-75$

$\Rightarrow 5x=735\Rightarrow x=\frac{135}{5}=27$

$\therefore$ Required percentage of benzene = 27%