One type of wine contains 15% alcohol, the other contains 20% alcohol. A container is filled with 2 parts of the first wine and 3 parts of the second wine. What is the percentage of alcohol in the new mixture.

20%

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18%

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22%

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16%

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Solution

The correct option is B 18%

$\frac{20 - x}{x - 15} = \frac{2}{3}$
$60 - 3 x = 2 x - 30 90 = 5 x x = 18 %$

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One type of wine contains 15% alcohol, the other contains 20% alcohol. A container is filled with 2 parts of the first wine and 3 parts of the second wine. What is the percentage of alcohol in the new mixture.

The correct option is B 18% 20−xx−15=23 60−3x = 2x−3090 = 5xx = 18%

The correct option is B 18%

$\frac{20 - x}{x - 15} = \frac{2}{3}$
$60 - 3 x = 2 x - 30 90 = 5 x x = 18 %$