Question

One unpaired electron in atom contributes a magnetic moment of 1.1 BM. The magnetic moment of $Cr$ (Atomic number 24) is:

• A. 4.6
• B. 5.6
• C. 6.6
• D. 7.6

Answer 1

Answer: (C)

6.6

$Cr(z=24)\Rightarrow \left[Ne\right]{3s}^2{3p}^6{4s}^1{3d}^5$

$n=6$

Now, $\mu =\sqrt{n(n+2)}$

$\mu =\sqrt{6\left(8\right)}=\sqrt{48}=6.6BM$